Ask a New Question

Question

Given the ellipse with foci at (5,3) and (5,-5) and a major axis length of 12, determine the center using ( , ) and the denominators of the equation

Center(x )^2/?, (y )^2/?=1
13 years ago

Answers

Steve
center is halfway between foci, at (5,-1)
semi-major axis vertical, length 6
for semi-minor axis, b^2 = a^2 - c^2 = 36-16=20

(x-5)^2/20 + (y+1)^2/36 = 1

13 years ago

Related Questions

Find the foci of the ellipse: (x^2/400)+(y^2/625)=1 what is the foci of the ellipse X2 over 81 + Y2 over 49=1 what is the foci of the ellipse (x+5)^2/4+(y-1)^2/16=1 find the foci of the ellipse (x+5)^2/4+(y-1)^2/16=1 the foci of an ellipse are (0,2) (0,-2) and the eccentricity is 1/2. determine the equation of the e... An ellipse has foci (0,+-3) and vertices (0,+-4). What is the eccentricity of the ellipse? Please h... Locate the foci of the ellipse. Show your work. 𝑥2/36+ y2/11=1 Locate the foci of the ellipse. Show your work. x^2/36+y^2/11=1 c^2=a^2-b^2 c^2=36-11 c^2=25... the foci of the ellipse given by the equation 100x2 + 25y2 = 2500? The ellipse has foci (0, 3) and (0, –3) and vertices (0, 5) and (0, –5);
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use