Asked by rui rui
Find the foci of the ellipse whose major axis has endpoints $(0,0)$ and $(13,0)$ and whose minor axis has length 12.
Answers
Answered by
Steve
clearly the major axis has length 13, and the minor axis has length 12. So
a = 13/2
b = 6
c^2 = a^2-b^2 = 25/4, so c = 5/2
The center is at (13/2,0), so
h = 13/2 and k=0
The foci are at (h±c,k)
Since the major axis is horizontal, that means the equation is
(x-h)^2/a^2 + (y-k)^2/b^2 = 1
(x - 13/2)^2/(13/2)^2 + y^2/6^2 = 1
see
http://www.wolframalpha.com/input/?i=ellipse+%28x+-+13%2F2%29^2%2F%2813%2F2%29^2+%2B+y^2%2F6^2+%3D+1
a = 13/2
b = 6
c^2 = a^2-b^2 = 25/4, so c = 5/2
The center is at (13/2,0), so
h = 13/2 and k=0
The foci are at (h±c,k)
Since the major axis is horizontal, that means the equation is
(x-h)^2/a^2 + (y-k)^2/b^2 = 1
(x - 13/2)^2/(13/2)^2 + y^2/6^2 = 1
see
http://www.wolframalpha.com/input/?i=ellipse+%28x+-+13%2F2%29^2%2F%2813%2F2%29^2+%2B+y^2%2F6^2+%3D+1
Answered by
rui rui
tysm
Answered by
nommy
Find the foci of the ellipse whose major axis has endpoints $(0,0)$ and $(13,0)$ and whose minor axis has length 12.
the answers are (9,0) and (4,0).
the answers are (9,0) and (4,0).
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