Asked by JJ
A 1.065-g sample of an unknown substance is dissolved in 30.00 g of benzene; the freezing point of the solution is 4.25 degrees C. The compound is 50.69% C, 4.23% H, and 45.08% O by mass.
Info you might need on benzene:
Normal Freezing point,degrees C: 5.53
Kf, degrees m^1: 5.12
Normal boiling point, degrees C: 80.10
Kb, degrees C m^-1: 2.53
Answer: C6H6O4
Info you might need on benzene:
Normal Freezing point,degrees C: 5.53
Kf, degrees m^1: 5.12
Normal boiling point, degrees C: 80.10
Kb, degrees C m^-1: 2.53
Answer: C6H6O4
Answers
Answered by
DrBob222
Follow the problems you've already done above on freezing points.
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