Question

A 1.065-g sample of an unknown substance is dissolved in 30.00 g of benzene; the freezing point of the solution is 4.25 degrees C. The compound is 50.69% C, 4.23% H, and 45.08% O by mass.


Info you might need on benzene:

Normal Freezing point,degrees C: 5.53
Kf, degrees m^1: 5.12
Normal boiling point, degrees C: 80.10
Kb, degrees C m^-1: 2.53

Answer: C6H6O4
Follow the problems you've already done above on freezing points.

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