A sample of unknown ore was analyzed and fgound to contain 12.7% Al, 19.7% N,and 67.6% O. What is the empirical formula of this ore?

Answer 1

Take a 100 g sample. This will give you
12.7g Al
19.7g N and
67.6% O.

Now convert grams to moles. moles = grams/molar mass

Finally, find the molar ratio of the numbers to each other with the smallest being 1.00. You can best do that by dividing the smallest number by itself (so you get 1.00 for that), then divide the other numbers by the same small number. Then round to whole numbers.
You will get something like
AlxNyOz where x,y, and z are the ratios you obtained above.
Post your work if you get stuck.

Answer 2

I don't understand how to do any of this stuff. it just goes over my head.

Answer 3

And you didn't show any work.Your first step is to convert grams to moles and I gave you the formula for that.

Answer 4

12.7 G Al/ 27 G=0.47
19.7 G N/ 14 G=1.4
67.6 G O/16 G=4.22

0.47/0.47=1
1.4/0.47=3
4.22//0.47=9

AlN3O9