Question

HELP!
an object moves in a straight line given by s=2x^2-3t where s is in meters and t is the time in seconds the object is in motion. how long to nearest tenth will it take to move 17 meters?

my attempt
s=2t^2-3t
17=2t^2-3t
-17=-17
0=2t^2-3x-17
t=-b +or- sqrtb^2-4ac/2a
t=-(-3)+or-sqrt-3^2-4(2)(-17)/2(2)

Did I do all of the correct steps? I think I did but this is really confusing

Answer 1

I have worked it more.....
t=3+or-sqrt9+136/4
t=3+or-sqrt145/4 (is this my answer?)

Answer 2

yes, you are right, but when typing on here you should use brackets to establish the correct order of operation

t = (3 ± √145)/4

I got the ± by holding down the Alt key and at the same time punching in 241 on the number key pad, then releasing the Alt key

I got the √ by holding down the Alt key and at the same time punching in 251 on the number key pad, then releasing the Alt key

I am using a PC with Firefox on XP
It did not work on my Apple IBook laptop