Asked by anonymous
An object moves around x^2 + y^2 = 25 (which represents a
circle whose radius is 5 meters) at a constant speed. At time
t = 0 seconds, the object is at (5, 0). When t = 1, it is at (4, 3).
Where is the object when t = 2? when t = 3? when t = n?
What is the object’s speed? At what times does the object return to (5, 0)? an explanation on how to start would be helpful plz thx
circle whose radius is 5 meters) at a constant speed. At time
t = 0 seconds, the object is at (5, 0). When t = 1, it is at (4, 3).
Where is the object when t = 2? when t = 3? when t = n?
What is the object’s speed? At what times does the object return to (5, 0)? an explanation on how to start would be helpful plz thx
Answers
Answered by
oobleck
in 1 second, it has moved through an angle of θ radians, where
tanθ = 3/4
so after n seconds, it will have moved through an angle of
Ø = n arctan(3/4)
Its speed is s = rθ m/s
it will be back at (5,0) when t = 2π/θ
tanθ = 3/4
so after n seconds, it will have moved through an angle of
Ø = n arctan(3/4)
Its speed is s = rθ m/s
it will be back at (5,0) when t = 2π/θ
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