Question

1. A 0.20 kg object moves at a constant speed in a horizontal circular path of radius "r" while suspended from the top of a pole by a string of length 1.2 m. It makes an angle of 62 degrees with the horizontal. What is the speed of this object?


2. An object of mass 3 kg is traveling in a horizontal circular path of radius 1.2 m while suspended by a piece of string length 1.9 m. It makes an angle of 39 degrees with the horizontal. What is the centripedal force on the mass?

Answer 1

The object is in equilibrium due to three forces: Tension T of the string, centripetal force C, and weight W.

Since C and W are orthogonal (at right angles), T can be resolved into two components in these directions, each opposing C and W.

In brief, tan(62°)=W/C

Thus the vertical component of T is mg.

The horizontal component is the centripetal force, mv²/r, where r is the horizontal radius, r=Lcos(θ), where L=length of string, and θ=62°.

Thus
mg/(mv^2/(1.2*cos(62°)))=tan(62°)

Solve for v. I get v=1.714 m/s

Answer 2

when an object moves in a circular path it changes direction and is therefore accelerating a force pushes the object toward the center of the circle what is the name of that force