Asked by robbi
A 4.3kg object moves across a floor with a velocity of + 8.2 m/s and slides to rest in
5.8 s. The net force producing this acceleration is:
5.8 s. The net force producing this acceleration is:
Answers
Answered by
Henry
V = Vo + a*t
V = 0
Vo = 8.2 m/s
t = 5.8 s.
Solve for a (It will be negative).
F = m*a
V = 0
Vo = 8.2 m/s
t = 5.8 s.
Solve for a (It will be negative).
F = m*a
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