Asked by Sammie

A tire 0.500 m in radius rotates at a constant rate of 200 rev/min. Find the speed and acceleration of a small stone lodged in the tread of the tire ( on its outer edge ).
Answered by Henry
C = pi * 2r = 3.14 * 1.0 = 3.14 m. =
Circumference.

V = 200rev/min * 3.14m/rev * 1min/60s =
10.5 m/s.
Answered by Anonymous
May God almighty blessed you more for you help thank you
Answered by Anton
the solution of it.
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