Question

A tire 0.500 m in radius rotates at a constant rate of 200 rev/min. Find the speed and acceleration of a small stone lodged in the tread of the tire ( on its outer edge ).
Henry
C = pi * 2r = 3.14 * 1.0 = 3.14 m. =
Circumference.

V = 200rev/min * 3.14m/rev * 1min/60s =
10.5 m/s.
Anonymous
May God almighty blessed you more for you help thank you
Anton
the solution of it.