Asked by Sammie

A tire 0.500 m in radius rotates at a constant rate of 200 rev/min. Find the speed and acceleration of a small stone lodged in the tread of the tire ( on its outer edge ).

Answers

Answered by Henry
C = pi * 2r = 3.14 * 1.0 = 3.14 m. =
Circumference.

V = 200rev/min * 3.14m/rev * 1min/60s =
10.5 m/s.
Answered by Anonymous
May God almighty blessed you more for you help thank you
Answered by Anton
the solution of it.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions