Question

A tire has a radius of 0.355 m. The tire rolls without slipping a distance of 12.7 meters. What angular displacement (in radians) did a point on the tread of the tire turn through?
Circumference = pi*2r = 3.14 *2*0.355 = 2.23m.

Disp. = 12.7m * 1rev/2.23m * 6.28rad/rev = 35.8rad.

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