Asked by cabarles
a tire 0.500 m in radius rotates at a constant rate of 200 rev/min.find the speed and accelation of a small stone lodge in the thread(on its outer edge).
Answers
Answered by
Henry
C = pi * 2r = 3.14 * 1 = 3.14 m.
V=200rev/min * 3.14m/rev * 1min/6=10.5 m/s.
V=200rev/min * 3.14m/rev * 1min/6=10.5 m/s.
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