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Test for convergence or divergence. Indicate the test that was used and justify your answer.

Sigma (lower index n = 4; upper index infinity) 1/(3n^2-2n-15)
12 years ago

Answers

Steve
3n^2-2n-15 > n^2 for n>=4,

the series converges since 1/n^2 converges
12 years ago

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