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Test for convergence:
(n+5)/((n^7+n^2)^(1/3)) from 1 to inf.

I cannot figure out which test to use. any help would be great!
9 years ago

Answers

Steve
you know that 1/n^p converges for p>1.

Loosely,
(n+5)/((n^7+n^2)^(1/3))
< (n+5)/n^(7/3)
< (n+5)/n^2.33
< 1/n^1.33
so it converges
9 years ago

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