Asked by Bill
Determine the convergence or divergence:
An=(-1)^n(n/(n+1))
An=(-1)^n(n/(n+1))
Answers
Answered by
bobpursley
A(n+1)= -1^(n+1) (n+1)/(n+2)
A(n+1)/An= -1* 1/n * 1/(n+2) which as n >> large, converges to zero.
A(n+1)/An= -1* 1/n * 1/(n+2) which as n >> large, converges to zero.
Answered by
Dovlet
I would reccomend you to open your book and spend a few minutes ;)