Asked by Bill
                Determine the convergence or divergence:
An=(-1)^n(n/(n+1))
            
        An=(-1)^n(n/(n+1))
Answers
                    Answered by
            bobpursley
            
    A(n+1)= -1^(n+1) (n+1)/(n+2)
A(n+1)/An= -1* 1/n * 1/(n+2) which as n >> large, converges to zero.
    
A(n+1)/An= -1* 1/n * 1/(n+2) which as n >> large, converges to zero.
                    Answered by
            Dovlet
            
    I would reccomend you to open your book and spend a few minutes ;) 
    
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