Question
Determine the convergence or divergence of the series. Find the limit. Indicate the test that was used and justify your answer by showing evidence why the test succeeds or fails.
Sigma (lower index n = 1; upper index infinity) 12/[n(n+3)]
Sigma (lower index n = 1; upper index infinity) 12/[n(n+3)]
Answers
we know that sum 1/n^2 = pi/6
Since n(n+3) > n^2, it also converges
Since n(n+3) > n^2, it also converges
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