Question
test the series for convergence or divergence
the series from n=0 to infinity of
(x^2+1)/(x^3+1)
I said that due to the limit comparison test this converges at 1
the series from n=0 to infinity of
(x^2+1)/(x^3+1)
I said that due to the limit comparison test this converges at 1
Answers
<<the series from n=0 to infinity of
(x^2+1)/(x^3+1)>>
Where did the x come from? Shouldn't he variable be n?
For large n, it approaches the sum of 1/n with n going to infinity, which does NOT converge. You can prove that with the "integral test". It behaves like log n as n-> infinity
(x^2+1)/(x^3+1)>>
Where did the x come from? Shouldn't he variable be n?
For large n, it approaches the sum of 1/n with n going to infinity, which does NOT converge. You can prove that with the "integral test". It behaves like log n as n-> infinity