Asked by Youssef
Three charges are located at the corners of a rectangle as follows:
Charge A: lower left corner, -3.0 μC
Charge B: upper left corner, -6.1 μC
Charge C: upper right corner, +2.7 μC
The distance between A and B is 0.16 m and between B and C it is 0.25 m.
How much work must an external force acting on the particles (like, your hands) do in order to move the charges infinitely far from each other?
Charge A: lower left corner, -3.0 μC
Charge B: upper left corner, -6.1 μC
Charge C: upper right corner, +2.7 μC
The distance between A and B is 0.16 m and between B and C it is 0.25 m.
How much work must an external force acting on the particles (like, your hands) do in order to move the charges infinitely far from each other?
Answers
Answered by
bobpursley
Simple.
The energy to do this will be equal to the PE the system has:
PE=k(Q1*Q2)/d12 +k(Q1Q3)/d13 +kQ2Q3/d23
And what is neat, you do this by moving only two charges, that puts all three infinitely apart.
The energy to do this will be equal to the PE the system has:
PE=k(Q1*Q2)/d12 +k(Q1Q3)/d13 +kQ2Q3/d23
And what is neat, you do this by moving only two charges, that puts all three infinitely apart.
Answered by
steave
1.49J