Asked by srdja
Charges of 4 µC are located at x = 0, y = 2.0 m and at x = 0, y = -2.0 m. Charges Q are located at x = 4.0 m, y = 2.0 m and at x = 4.0 m, y = -2.0 m. The electric field at x = 0, y = 0 is (4 ✕ 103 N/C) i. Determine Q.
Answers
Answered by
Damon
at (0,0) the fields from the first two charges cancel each other.
to get a field at (0,0) in the y direction the x components of charges Q must cancel.
Therefore one must be +Q and the other -Q
If the field is up (+ i direction)
the one below the axis is +Q and the one above the axis is -Q
each contributed half of the E field
distance = d = sqrt (20) = 2 sqrt 5
so d^2 = 20
E = 2 *10^3 = k Q/20
to get a field at (0,0) in the y direction the x components of charges Q must cancel.
Therefore one must be +Q and the other -Q
If the field is up (+ i direction)
the one below the axis is +Q and the one above the axis is -Q
each contributed half of the E field
distance = d = sqrt (20) = 2 sqrt 5
so d^2 = 20
E = 2 *10^3 = k Q/20
Answered by
srdja
so Q = (2*10^3*20)/(8.99*10^9) ?
i calculated that and it doesnt give me the correct answer
i calculated that and it doesnt give me the correct answer
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.