let q1= -2C, q2= +5C, q3= -4C
also r13=10+4=14cm=0.14m
& r23= 4cm = 0.04m
a) Force on q3 due to q2:
F32= k*q3*q2/(r23)^2 towards left
b)Force on q3 due to q1:
F31= k*q3*q1/(r13)^2 towards right
c) Net force on q3 = F32-F31
a.what is the force exerted on the -4 C by the +5C charge?
b.what is the force exerted on the -4 C by the -2 C charge?
c.what is the net force exerted on the -4 C charge?
also r13=10+4=14cm=0.14m
& r23= 4cm = 0.04m
a) Force on q3 due to q2:
F32= k*q3*q2/(r23)^2 towards left
b)Force on q3 due to q1:
F31= k*q3*q1/(r13)^2 towards right
c) Net force on q3 = F32-F31
F = k * (|q1| * |q2|) / r^2
Where F is the force between the charges, k is Coulomb's constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
a. To find the force exerted on the -4 C charge by the +5 C charge, we can use the equation mentioned above. We know that the magnitude of the +5 C charge is 5 C and the distance between the charges is 4 cm (0.04 m) since they are located 4 cm apart. Plugging these values into the equation, we have:
F = (8.99 x 10^9 Nm^2/C^2) * (5 C * 4 C) / (0.04 m)^2
Calculating this, we find:
F = 449,500 N
Therefore, the force exerted on the -4 C charge by the +5 C charge is 449,500 N.
b. Similarly, to find the force exerted on the -4 C charge by the -2 C charge, we use the same equation. The magnitude of the -2 C charge is 2 C, and the distance between the charges is 4 cm (0.04 m) since they are located 4 cm apart. Plugging these values into the equation, we have:
F = (8.99 x 10^9 Nm^2/C^2) * (2 C * 4 C) / (0.04 m)^2
Calculating this, we find:
F = 449,500 N
Therefore, the force exerted on the -4 C charge by the -2 C charge is also 449,500 N.
c. The net force exerted on the -4 C charge is the vector sum of the forces exerted by the +5 C and -2 C charges. Since they are both acting in the same direction (both attracting the -4 C charge), we can simply add their magnitudes to find the net force. The net force is calculated by:
Net force = Force exerted by the +5 C charge + Force exerted by the -2 C charge
Net force = 449,500 N + 449,500 N
Calculating this, we find:
Net force = 899,000 N
Therefore, the net force exerted on the -4 C charge is 899,000 N.