Asked by Sasha
charges of +1.000 C are located at the corners of a 45-45- right triangle which has a hypotenuse that is 1.414 m long. Determine the resultant force on the charge located at the vertex of the right angle.
Answers
Answered by
drwls
The two charges at the 45 degree corners are each 1.0 m from the charge at the right angle.
There are two perpendicular forces acting on the right angle vertex charge. Each has magnitude
k Q^2/(1.0m^2)
where Q = 1.0C and k is the Coulomb constant. (look it up)
Add thse two forces as vectors. The magnitude should be sqrt2 * the magnitude of the individual forces. The direction will be along the bisector of the right angle.
There are two perpendicular forces acting on the right angle vertex charge. Each has magnitude
k Q^2/(1.0m^2)
where Q = 1.0C and k is the Coulomb constant. (look it up)
Add thse two forces as vectors. The magnitude should be sqrt2 * the magnitude of the individual forces. The direction will be along the bisector of the right angle.
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