Asked by Chris
If 225.O grams of NO react with excess NH3,how many grams of H2O are produced
Answers
Answered by
Devron
The molecular formula is as followed:
6NO + 4NH3 --->5N2 + 6H2O
The ratio of moles of NO to H2O is 1 to 1.
225.0g of NO/30.01 g of NO/mol= moles of NO
Moles of NO=Moles of H20
Moles of H2O *18.02g of H2O/mol= mass of H2O
6NO + 4NH3 --->5N2 + 6H2O
The ratio of moles of NO to H2O is 1 to 1.
225.0g of NO/30.01 g of NO/mol= moles of NO
Moles of NO=Moles of H20
Moles of H2O *18.02g of H2O/mol= mass of H2O
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