Asked by Anonymous
If 45.3 grams of aluminum react with an excess of oxygen, as shown in the balanced chemical equation below, how many grams of aluminum oxide can be formed?
4Al + 3O2 2Al2O3
4Al + 3O2 2Al2O3
Answers
Answered by
DrBob222
Follow the steps in this example.
http://www.jiskha.com/science/chemistry/stoichiometry.html
http://www.jiskha.com/science/chemistry/stoichiometry.html
Answered by
Anonymous
1. 4Al + 3O2 = 2Al2O3
2. Set the equation. mol ratio is 4:2
45.3 g Al * (1 mol Al / 26.982 g Al) * (2 mol AlO / 4 mol Al) * (101.964 g AlO / 1 mol AlO)
= 85.63 g Al2O3
2. Set the equation. mol ratio is 4:2
45.3 g Al * (1 mol Al / 26.982 g Al) * (2 mol AlO / 4 mol Al) * (101.964 g AlO / 1 mol AlO)
= 85.63 g Al2O3
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