An electron experiences 1.2 x 10^-3 force when it enters the external magnetic field, B with a velocity v. What is the force experienced by the electron if the magnetic field is increased two times and the velocity is decreased to half?

Question

Any help would be greatly appreciated

Answer 1

F=qvBsinα
F1=q(v/2)(2B)sinα = qvBsinα = 1.2x10^-3 T

Answer 2

Thanks so much Elena