Question
A 6 mC charge experiences a force of 6 N directed north. What is the electric field (magnitude and direction) at the location of the charge?
Would the direction still be north? And the magnitude 1000?
Would the direction still be north? And the magnitude 1000?
Answers
E = F/q = 6/6•10^-3 =100 V/m.
The direction still be north.
magnitude of the electric field is
E = k •q /r²,
therefore, E ~ 1/r²
The direction still be north.
magnitude of the electric field is
E = k •q /r²,
therefore, E ~ 1/r²