Asked by Josh
A -3.5uC charge experiences a 13 ihat-N electric force in a certain electric field.What force would a proton experience in the same field?
I got -7.28*10^-18
from (1.6*10^-19)(-45.5)
I got -45.5 from multiplying 13 by -3.5
What am I doing wrong?
I got -7.28*10^-18
from (1.6*10^-19)(-45.5)
I got -45.5 from multiplying 13 by -3.5
What am I doing wrong?
Answers
Answered by
bobpursley
I would have just done a proportion:
Force= 13N*(-3.5E-6/1.6E-19)= I don't get your answer.
Force= 13N*(-3.5E-6/1.6E-19)= I don't get your answer.
Answered by
Josh
I got -2.84E14 plugged it in and got the wrong answer
Answered by
bobpursley
change the proportion to
13N(1.6E-19/3.5E-6)
check that thinking.
13N(1.6E-19/3.5E-6)
check that thinking.
Answered by
ozzy
ok both ways were wrong, you use cross multiplication: 1.6E-19/F x -3.5E-6/13N
F(on proton)= (13N *1.6E-19)/ -3.5E-6
F(on proton)= (13N *1.6E-19)/ -3.5E-6
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