Asked by Sam
An electron experiences a force of 12 mN in the positive x-direction in an electric field. What is the magnitude and direction of the electric field?
Answers
Answered by
drwls
E field = Force/(electron charge)
Divide 12*10^-3 N by the electron charge in Coulombs.
You may need to look that up.
1 Newton per Coulomb is the same as 1 Volt per meter.
Divide 12*10^-3 N by the electron charge in Coulombs.
You may need to look that up.
1 Newton per Coulomb is the same as 1 Volt per meter.