F=qvBsinα
F1=q(v/2)(2B)sinα = qvBsinα = 1.2x10^-3 T
An electron experiences 1.2 x 10^-3 force when it enters the external magnetic field, B with a velocity v. What is the force experienced by the electron if the magnetic field is increased two times and the velocity is decreased to half?
Okay so I know there's the formula
F = BIlsin0
But isn't the question missing some information? I'm very confused
1 answer