Question
A guitar string is 90cm long and has a mass of 3.8g . The distance from the bridge to the support post is L=62cm , and the string is under a tension of 540N . What are the frequencies of the fundamental and first two overtones?
Answers
Elena
v = sqrt(TL₀/m)=
=sqrt(540•0.9/0.0038) =357.6 m/s.
Fundamental frequency f:
λ=v/f=2L
f=v/ λ=v/2L=357.6/2•0.62 = 288.4 Hz.
f1=v/λ₁=v/L=357.6/0.62=576.8 Hz
f2=v/λ₂=v/(2L/3)=3 v/2L=865.2 Hz
=sqrt(540•0.9/0.0038) =357.6 m/s.
Fundamental frequency f:
λ=v/f=2L
f=v/ λ=v/2L=357.6/2•0.62 = 288.4 Hz.
f1=v/λ₁=v/L=357.6/0.62=576.8 Hz
f2=v/λ₂=v/(2L/3)=3 v/2L=865.2 Hz