Answers by visitors named: Phil

Can't i figure out if its increasing or decreasing using the first derivative test? What is the point of the second derivative test?

My thesis statement has to be objective (supporting both sides) as my essay has to be objective too. That's why I'm having trouble with it. Thanks

You're right. Please help with reconstructing my new thesis statement. I want to make it short, but strong, supporting dress codes in schools. "Even though enforcing dress codes in schools infringes upon students rights, dress codes should be enforced in schools because it helps to reduce non-academic distractions and it encourages discipline among students."

That was in 1795, this treaty Im talking about during the articles of confederation 1781 - 1789. It was one of the reasons why government under the Articles was weak, and it had to do with sectionalism.

That's it! Thanks!

30 days later. this is like least common multiples... 2, 5, 15. the least common multiple is 30.

i found x value of P how do I find the y value of P?

Well why didn't he just sell the scrap wood? It's not economically efficient if he throws out something he could sell. And yes, of course it depends how much it cost those managers and workers in time to save the $7000 and what else could they have been working on.

Ok so I got the first and last parts correct from what i did, but the second part is still messing me up. Do i enter 1/2 the time i calculated in the first question?

Ok, I think I got it. Are these free body diagrams correct? (ignore the dots) TIRE+BOY: T F |.| .| W FREE END: .T .| .| .F SYSTEM: .F .| .| .T.....(This tension is down) T.F....(This tension is up) |.| .| .W CANCELING TENSIONS: 2F | | W 2F=W so F=(1/2)W

Now I'm confused. Why does changing the direction of a force double it? I'm also confused about whether the tension is a reaction to the weight of the tire and the boy or the force that the boy pulls down on the rope with. Also if the force in the free body diagram of the system were another person pulling the tire and the boy up, why would the force not be half the weight in that case?

Yes "A" has reflective symmetry, not rotational symmetry.

37 is a and 38 is i think a and b

This implies that the double and triple bond are adjacent to eachother, so that would give the N an expanded octet of 10 electrons, but I thought that only happened after P?

(brass diameter)*(1+(brass coefficient)*(change in brass temperature)) = (iron diameter)*(1+(iron coefficient)*(change in iron temperature)) where: brass coefficient = 19*10^-6 K^-1 iron coefficient = 12*10^-6 K^-1

Nevermind. The answer is 250 degrees Celsius. Duh!

The mass times the coefficient of friction

They're all the same size.

What's the least common multiple of 2 and 2.5?

Trista is almost correct. However she failed to realize that the problem called for 100 mg which is equal to 0.1 grams. This means that (7.05x10^-3)g/L / 0.1g = 0.0705/1L (Where the L is in the denominator). So in order to finalize this problem all you have to do is take the inverse to get 1L/0.0705 = 14.2 L The correct anwser.

1. You are correct. The strength of a weak acid is proportional to its dissociation constant, which is directly proportional to the concentration of ions and inversely proportional to the concentration of the undissociated acid molecules. 2. Yes, this is correct. The pH decreases because pH = -log([H+]). If the concentration of a weak acid goes up, the concentration of H+ will also go up. However, the negative sign in that expression means that the pH will go down. 3. Yes, that is correct. Lower pH means higher acidity/stronger acid. 4. Yup. Just as pH decreases with higher concentrations of acid, it will increase with higher concentrations of base.

You are actually really close. First remember that ΔG = Greactants - Gproducts. In this case the equation is: Ba2+ + NO3- -> Ba(NO3)2 But that equation isn't balanced! For this to work you have to balance the equation first like so: Ba2+ + _2_NO3- -> Ba(NO3)2 This means NO3 contributes twice as much. In the next step just be very careful with your signs. One missed - and you could get an answer 2 million times bigger than you expect. (-561kj/mole) + 2*(-109kj/mole) - (-797 kj/mole) = 18 kj/mole -18/RT = ln Ksp Hope this helps :)

This is an example of a combustion reaction involving a hydrocarbon (in this case propane) reacting with oxygen. The products of such reactions are almost always water and carbon dioxide. C3H8(g) + O2(g) → H2O + CO2 First balance the number of Carbons on both sides. There are 3 Carbon atoms for every propane molecule and 1 for each carbon dioxide. C(3)H8(g) + O2(g) → H2O + _X_CO2 Second balance the number of Hydrogens. Here we have 8 for each propane and 2 for each water. C3H(8)(g) + O2(g) → _Y_H(2)O + X*CO2 Finally count up all the oxygen atoms on the right side of the equation and balance that with the oxygen molecules on the left. C3H8(g) + _Z_O2(g) → Y*H2O + X*CO2 where Z = X/2 + Y Sometimes after this you will end up with fractions, which is okay, but if you prefer you can multiply both sides of the equation by the lowest common denominator to get rid of the fractions. In this case you shouldn't have any fractions. Oh, and don't forget to include the states. CO2 is obviously a gas and H2O will likely also be a gas (water vapor) due to the heat yielded by the reaction. Hope this helps.

My answers would be a, b, and d, where b and d are the same force. This assumes you are traveling very fast.

1. P = positive results / total attempts. In this case, 11/50 = .22 = 22% 2. Increase the sample size. The more data he accrues, the closer the experimental probability will be to the theoretical probability.

hah I love how everyone in physics with Kaminsky is looking here

Force equals mass times acceleration...the mass of your vehicle is the same, always. The acceleration is also to be considered the same for both problems. So if both equations, (one for collision with wall, and one for other car) have the same numbers, then the forces are equal. Another way to look at it is to think about the collision itself: what is the speed at the point of impact? It is the same regardless of what object you hit, a wall, a car, or a semi truck...zero.

A rectangle is 5 times longer then it is wide. If perimeter of the rectangle is 222m. What are its dimensions

The way this is written you need to A:conduct three trials using three different coins (1 for each trial). For each trial flip the coin three times & record the results (heads even & tails odd). Each flip represents one of the three misses for that route. B: Actually do the experiment/trials three separate times and record the results. C: Calculate the experimental Probability based on the results of your experiment. (answers will differ depending on the results of your experiment.

The answer is 200N in the sense that an increase in force will produce an increase in the acceleration.

Kole is right but how would you find velocity

you screwed buddy

205.8 J/s

For the first one, 13% are Civil Engineers, but where do I go from there?

Okay, I just figured out the answer and where my confusion came from. Correct me if I am wrong. x/0.104+0.950x = 4.27/7.98 7.98x = 0.44408+4.0565x 7.98x-4.0565x = 0.44408 3.9235x = 0.44408 x = 0.44408/3.9235 x = 0.1131846566

Unfortunately, there is often more than one way to answer a textbook example. In class, it's one way (the quickest way), and in the textbook, it's another. The "quick" way is fine for tests and exams... but it is useful to me that I learn alternate methods as well. A step by step approach was lacking from the textbook explanation (my only complaint). Anyway; thanks for your suggestion. I will give your method a shot.

5.34m/s^2

If a pie was cut into four equal pieces, adjacent angles would add up to 180 degrees, meaning they are supplementary angles.

C B D IS CORRECT

thanks!

Question number 1 is simply asking what the weight of the second heating needs to be in order for the compound to be "dehydrated." The two weights need to be within .05g in order for the sample to be dehydrated. In this case: 4.8702g(initial mass)- 3.0662(after first heating)= 1.804g 3.0662(mass after first heating)- .05g(maximum variance in mass in order to be dehydrated)= 3.0162g Keep in mind the .05g variance is used in order to determine "constant weight."

The conversion is 1:6 180N/6=30N on the moon

Its B Duhhhhh easy

IDK THIS IS REALLY HARDD

Rawr XD

Yep you got it!

Yep! You got it!

Good Question

I figured it out.

y