Asked by Jenna
A particular guitar string is supposed to vibrate at 220 , but it is measured to vibrate at 230 .
By what percent should the tension in the string be changed to correct the frequency?
I have been working for 7 hours of hw! Please help!
By what percent should the tension in the string be changed to correct the frequency?
I have been working for 7 hours of hw! Please help!
Answers
Answered by
bobpursley
isnt v=sqrt(tension)
but f*lambda= v= sqrt(tension). So leaving the lambda constant, then f is proportional to sqrt tension
230/220= sqrt (tension/orgtension)
square both sides, solve for tension, then find the percent increase.
but f*lambda= v= sqrt(tension). So leaving the lambda constant, then f is proportional to sqrt tension
230/220= sqrt (tension/orgtension)
square both sides, solve for tension, then find the percent increase.
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