Asked by melissa
A particular guitar string is supposed to vibrate at 210Hz , but it is measured to vibrate at 220Hz
By what percent should the tension in the string be changed to correct the frequency?
By what percent should the tension in the string be changed to correct the frequency?
Answers
Answered by
Elena
v=sqrt(T•L/m)
λ=v/f => f=v/λ= sqrt(T•L/m)/ λ
f₁/f₂={sqrt(T₁•L/m)/ λ}/{sqrt(T₂•L/m)/ λ}
(f₁/f₂)² =T₁/T₂
T₂=T₁(f₂/f₁)²
(T₂-T₁)/T₁=(T₂/T₁) -1=(f₂/f₁)²-1=(220/210)²-1=0.0975.
=> 9.75%
λ=v/f => f=v/λ= sqrt(T•L/m)/ λ
f₁/f₂={sqrt(T₁•L/m)/ λ}/{sqrt(T₂•L/m)/ λ}
(f₁/f₂)² =T₁/T₂
T₂=T₁(f₂/f₁)²
(T₂-T₁)/T₁=(T₂/T₁) -1=(f₂/f₁)²-1=(220/210)²-1=0.0975.
=> 9.75%
Answered by
Ethan
Instead of subtracting 1 at the end, I divided the result by 1 and then subtracted from 1.
1 - (1 / (220/210)²) = 8.89%
1 - (1 / (220/210)²) = 8.89%
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