Asked by tommy
A 200.0 N force moves a 120.0 kg crate on a friction less surface from rest to final speed of 9.6 m/s. what is the displacement of the crate at the time it reaches this speed ?
Answers
Answered by
Henry
a = F/m = 200/120 = 1.67 m/s^2.
V^2 = Vo^2 + 2a*d.
d = (V^2-Vo^2)/2a
d = (92.16-0)/3.34 = 27.6 m.
V^2 = Vo^2 + 2a*d.
d = (V^2-Vo^2)/2a
d = (92.16-0)/3.34 = 27.6 m.
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