Asked by Mary
An electric force moves a charge of +1.40 x 10^-4 C from point A to point B and performs 4.70 x 10^-3 J of work on the charge.
(a) What is the difference (EPEA - EPEB) between the electric potential energies of the charge at the two points?
____________J
(b) Determine the potential difference (VA - VB) between the two points.
____________V
(c) State which point is at the higher potential.
_____Point A
_____Point B
_____They are at the same potential.
(a) What is the difference (EPEA - EPEB) between the electric potential energies of the charge at the two points?
____________J
(b) Determine the potential difference (VA - VB) between the two points.
____________V
(c) State which point is at the higher potential.
_____Point A
_____Point B
_____They are at the same potential.
Answers
Answered by
drwls
(a) The electric potential energy decrease, (EPEA - EPEB), equals the work done by the force
(b) Divide (EPEA - EPEB) by the charge to get the electric potential difference
(c) (EPEA - EPEB) is positive, and so is VA - VB. That should tell you which is V higher.
(b) Divide (EPEA - EPEB) by the charge to get the electric potential difference
(c) (EPEA - EPEB) is positive, and so is VA - VB. That should tell you which is V higher.
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