Question

An electric force moves a charge of +1.65 multiplied by 10-4 C from point A to point B and performs 6.40 multiplied by 10-3 J of work on the charge.

(a) What is the difference (EPEA - EPEB) between the electric potential energies of the charge at the two points?
(b) Determine the potential difference (VA - VB) between the two points.
(c) State which point is at the higher potential.
(a) Work done by the field is MINUS the change of potential energy.
So the EPE change is -6.40*10^-3 J
Since they are asking for EPEA - EPAB, that is +6.40*10^-3 J.

(b) Divide the previous answer by the charge, 1.64*10^-4 C

(c) Point A has higher potential, since work was done on a positive charge going from A to B

Related Questions

An electric force moves a charge of +1.40 x 10^-4 C from point A to point B and performs 4.70 x 10^-... A charge of 28.0 is placed in a uniform electric field that is directed vertically upward and that... An electric force moves a charge of +1.80×10-4 C from point A to point B and performs +5.80×10-3 J o...