You need to provide units for the charge and the E-field. I assume they are Coulombs and Volts/meter, but unless you say what they are, you have not asked a proper physics question.
The work done on the charge will depend upon how far it moves.
A charge of 28.0 is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 4.00×104 . What work is done by the electric force when the charge moves
6 answers
I am so sorry my computer didn't transfer it
28nC
4.00*10^4N/C
.550m to the right
28nC
4.00*10^4N/C
.550m to the right
The force on the particle is
E*q = 4*10^4 N/C * 28*10^-9 C.
Multiply that by 0.550 m for the work done, in Joules.
(Volts/meter and Newtons/Coulomb are equivalent units)
E*q = 4*10^4 N/C * 28*10^-9 C.
Multiply that by 0.550 m for the work done, in Joules.
(Volts/meter and Newtons/Coulomb are equivalent units)
thnak you! Can you please help me with this one as well? Its the same problem:
2.40 at an angle of 45.0 downward from the horizontal?
2.40 at an angle of 45.0 downward from the horizontal?
sorry again my computer..2.4m
The work done will equal the force times the distance moved vertically (in the direction of the E field). You answer will contain a sin 45 = 0.707 factor.
The force will be up and you are moving the charge down, so potential energy will increase as work is done on the charge.
The force will be up and you are moving the charge down, so potential energy will increase as work is done on the charge.
1 answer