Asked by Anonymous

find the equation to the straight line which passes through the point of intersection of the line 3x+4y-1=0 and 5x+8y-3=0 and is perpendicular to the line 4x-2y+3=0
Answered by Steve
the two lines intersect at (-1,1)
The required slope is -1/2

SO, the desired line is

y-1 = -1/2 (x+1)
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