Asked by subash
Find the equation of the straight line that passes through the points (−1, 5) and (5, −1). Find the coordinates of the point where this line crosses the y-axis.
Answers
Answered by
drwls
The slope is [5 - (-1)]/(-1 -5) = -1
The equation is y = -x + b
To pass through (-1,5),
5 = 1 + b
b = 4
y = -x +4
The y-intercept is at (0,4) .
The equation is y = -x + b
To pass through (-1,5),
5 = 1 + b
b = 4
y = -x +4
The y-intercept is at (0,4) .
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