Asked by A GOODSTUDENT
Find the equation of the straight line passing through the point(3,-2) and making an angle of 60° with the line√3x+y-1=0
Plzz help someone
Plzz help someone
Answers
Answered by
Steve
since the line √3x+y-1=0 makes angle of -30° with the x-axis, the desired line is inclined at an angle of +30°. So, we have
y+2 = 1/√3 (x-3)
y = 1/√3 x - (2+√3)
or, as the other line is given is standard form,
x-√3y-(3+2√3) = 0
y+2 = 1/√3 (x-3)
y = 1/√3 x - (2+√3)
or, as the other line is given is standard form,
x-√3y-(3+2√3) = 0
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.