Asked by Anonymous
An object in launched directly upward at 54 feet per second (ft/s) from a platform 75 feet high. What will be the object's maximum height? When will it attain this height?
Answers
Answered by
bobpursley
PE at top=PE at launch+Initial KE
I recommend you change feet to meters...
mgh=mg(distancehigh)+1/2 m vi^2 solve for h.
I recommend you change feet to meters...
mgh=mg(distancehigh)+1/2 m vi^2 solve for h.
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