Asked by Titsuya
An object in launched directly upward at 64 feet per second from platform 80 feet high. its height is represented by the equation s ( t ) =- 16t +64t+80. What will be the object's maximum height?
Answers
Answered by
oobleck
as with all parabolas at^2 + bt + c, the vertex is at t = -b/2a
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