Question
An object is launched at 19.6 meters per second from a 58.8 meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = -4.9t2+ 19.6t + 58.8, where s is in meters.
a. When does the object strike the ground?
b. What was its maximum height?
c. How long will it take to reach its maximum height?
a. When does the object strike the ground?
b. What was its maximum height?
c. How long will it take to reach its maximum height?
Answers
Reiny
see this similar question
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http://www.jiskha.com/display.cgi?id=1461613740
Anonymous
iudk
Gizelle
a. 6 seconds