Asked by Anonymous

An object is launched at 19.6 meters per second from a 58.8 meter tall platform. The equation for the object's height s at time t seconds after launch is s(t) = -4.9t2+ 19.6t + 58.8, where s is in meters.
a. When does the object strike the ground?
b. What was its maximum height?
c. How long will it take to reach its maximum height?
Answered by Reiny
see this similar question

http://www.jiskha.com/display.cgi?id=1461613740
Answered by Anonymous
iudk
Answered by Gizelle
a. 6 seconds
There are no AI answers yet. The ability to request AI answers is coming soon!