Asked by dan

An object is launched at 9.8 meters per second from a 73.5-meter tall platform. The object's height s (in meters) after t seconds is given by the equation s(t)= -4.9t(-4.9t) - 9.8t = 73.5. When does the object strike the ground?

I literally have no idea where to start

Answers

Answered by Anonymous
You first multiply -4.9t by -4.9t.
Then you subtract 73.5 from both sides and from there you use the quadratic formula.
Answered by dan
thanks
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