Asked by Meera
find the derivative (df/dx) of the squareroot of sin4x
Answers
Answered by
Damon
d/dx (sin 4 x)^.5
= .5 [(sin 4x)^-.5 ](4 cos 4x)
= 2 cos 4x /sqrt(sin 4x)
= .5 [(sin 4x)^-.5 ](4 cos 4x)
= 2 cos 4x /sqrt(sin 4x)
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