Ask a New Question
Menu

find the the 2nd derivative and set equal to zero in order to find inflection points of the function

f(x)=1/(5x^2+4)

1 answer

I would write it as
f(x) = (5x^2 + 4)^-1

f'(x) = -(5x^2 + 4)^-2 (10x)
= -10x(5x^2 + 4)^-2

f''(x) = -10x(-2)(5x^2 + 4)^-3 (10x) - 10(5x^2 + 4)^-2
= -10(5x^2 + 4)^-3 [ 10x^2 + 5x^2 + 4 ]

can you set this equal to zero and solve?

check my arithmetic.
Similar Questions
  1. Given the function: f(x) = x^2 + 1 / x^2 - 9a)find y and x intercepts b) find the first derivative c) find any critical values
    1. answers icon 1 answer
  2. Given the function: f(x) = x^2 + 1 / x^2 - 9a)find y and x intercepts b) find the first derivative c) find any critical values
    1. answers icon 0 answers
  3. If f(x) = ln(x^2 + 9)a) find the local maximum and minimum values I found the derivative and set it equal to 0 but idk what to
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions