Asked by Carly
Find the derivative of:
y= 5^x + 15/x^6
I'm assuming I need to take the natural log of each side, but I get stuck after that part.
y= 5^x + 15/x^6
I'm assuming I need to take the natural log of each side, but I get stuck after that part.
Answers
Answered by
Damon
I would split it into two problems and add the result.
y = 5^x
ln y = x ln 5
y'/y = ln 5
y' = y ln 5
y' = 5^x ln 5
then
y = 15 x^-6
y' = 15(-6) x^-7
y' = -90/x^7
so finally
y' = 5^x ln 5 - 90/x^7
y = 5^x
ln y = x ln 5
y'/y = ln 5
y' = y ln 5
y' = 5^x ln 5
then
y = 15 x^-6
y' = 15(-6) x^-7
y' = -90/x^7
so finally
y' = 5^x ln 5 - 90/x^7
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