f= b(a+z^2)^-2
f'= -2(a+z^2)^-3 * 2z
=-4z/(a+z^2)^3
check that carefully.
Find the derivative of (b/(a+z^2))^2
Assuming that a and b are constants...
5 answers
How did you get the -2 at the beginning?
f=u^b
f'= b*u^(b-1)
in this case, b=-2
f'= b*u^(b-1)
in this case, b=-2
But why is b -2?
Check up the power rule in your notes.
d(x^n)/dx = nx^(n-1)
The power is -2 in the given question.
Remember: "check that carefully."
d(x^n)/dx = nx^(n-1)
The power is -2 in the given question.
Remember: "check that carefully."