Find the derivative of (b/(a+z^2))^2

Assuming that a and b are constants...

5 answers

f= b(a+z^2)^-2

f'= -2(a+z^2)^-3 * 2z

=-4z/(a+z^2)^3

check that carefully.
How did you get the -2 at the beginning?
f=u^b
f'= b*u^(b-1)

in this case, b=-2
But why is b -2?
Check up the power rule in your notes.
d(x^n)/dx = nx^(n-1)
The power is -2 in the given question.

Remember: "check that carefully."