Asked by Rene
Find the derivative of f(x)=ln(e^(2x)/((x^2-4)^3)
Please show detail so I can use for reference. Thanks!
Please show detail so I can use for reference. Thanks!
Answers
Answered by
Steve
If you mean
f(x)=ln(e^(2x)/((x^2-4)^3)) then that's
ln(e^2x)) - 3ln(x^2-4) = 2x - 3ln(x^2-4)
Now it's just easy stuff:
f' = 2 - 6x/(x^2-4)
f(x)=ln(e^(2x)/((x^2-4)^3)) then that's
ln(e^2x)) - 3ln(x^2-4) = 2x - 3ln(x^2-4)
Now it's just easy stuff:
f' = 2 - 6x/(x^2-4)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.