Find the derivative of f(x)=ln(e^(2x)/((x^2-4)^3)

Question

Please show detail so I can use for reference. Thanks!

Answer 1

If you mean

f(x)=ln(e^(2x)/((x^2-4)^3)) then that's

ln(e^2x)) - 3ln(x^2-4) = 2x - 3ln(x^2-4)

Now it's just easy stuff:

f' = 2 - 6x/(x^2-4)