Question
Find the derivative of y with respect to x:
y=(1+cos²x)^6
y'=6(1+cos²x)^5
How do you derive inside the brackets? The answer says -sin2x, but wouldn't it be -2sinx, using the chain rule.
y=(1+cos²x)^6
y'=6(1+cos²x)^5
How do you derive inside the brackets? The answer says -sin2x, but wouldn't it be -2sinx, using the chain rule.
Answers
You still have to differentiate the "inside"
d(1+cos^2x) = 2cosx(-sinx)
= -2sinxcox
= -sin 2x, one of the identities
so
y'=6(1+cos²x)^5(-sin2x)
= y'= -6(1+cos²x)^5(sin2x)
d(1+cos^2x) = 2cosx(-sinx)
= -2sinxcox
= -sin 2x, one of the identities
so
y'=6(1+cos²x)^5(-sin2x)
= y'= -6(1+cos²x)^5(sin2x)
Oh, I see it now, thanks!
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