Asked by Johnvon
Consider a simple pendulum of length 1.1 m with
m = 2.9 kg.
If the amplitude of the oscillation is 0.11 m (as measured along the circular arc along which it moves), what is the total mechanical energy of the oscillator?
____ Joules
m = 2.9 kg.
If the amplitude of the oscillation is 0.11 m (as measured along the circular arc along which it moves), what is the total mechanical energy of the oscillator?
____ Joules
Answers
Answered by
Jennifer
When all the mechanical energy is kinetic energy, the energy is
1/2*m*v^2 = 1/2*m*omega^2*r^2
where m is the mass, r is the radius, and omega is the angular velocity; For a pendulum, the angular velocity is given by omega = (g/r)^0.5
1/2*m*v^2 = 1/2*m*omega^2*r^2
where m is the mass, r is the radius, and omega is the angular velocity; For a pendulum, the angular velocity is given by omega = (g/r)^0.5
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.