Question
Consider a simple pendulum of length 1.1 m with
m = 2.9 kg.
If the amplitude of the oscillation is 0.11 m (as measured along the circular arc along which it moves), what is the total mechanical energy of the oscillator?
____ Joules
m = 2.9 kg.
If the amplitude of the oscillation is 0.11 m (as measured along the circular arc along which it moves), what is the total mechanical energy of the oscillator?
____ Joules
Answers
When all the mechanical energy is kinetic energy, the energy is
1/2*m*v^2 = 1/2*m*omega^2*r^2
where m is the mass, r is the radius, and omega is the angular velocity; For a pendulum, the angular velocity is given by omega = (g/r)^0.5
1/2*m*v^2 = 1/2*m*omega^2*r^2
where m is the mass, r is the radius, and omega is the angular velocity; For a pendulum, the angular velocity is given by omega = (g/r)^0.5
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