Asked by Anonymous
A simple pendulum, 2.0 m in length, is released from rest when the support string is at an angle of 25 from the vertical. What is the speed of the suspended mass at the bottom of the swing?
Answers
Answered by
drwls
Let A be the pendulum angle, which vaires sinusoidally with time. R is the pendulam length
R sin A = X
Xm = 2.0 sin 25 = 0.845 m is the oscillation amplitude (measured horizontally)
X = Xm sin (w t)
is the equation of motion
w is the angular frequency
w = sqrt(g/R) = 2.21 rad/s
Vmax = w*Xm = 2.21 rad/s*0.845 m
= 1.87 m/s
R sin A = X
Xm = 2.0 sin 25 = 0.845 m is the oscillation amplitude (measured horizontally)
X = Xm sin (w t)
is the equation of motion
w is the angular frequency
w = sqrt(g/R) = 2.21 rad/s
Vmax = w*Xm = 2.21 rad/s*0.845 m
= 1.87 m/s
Answered by
Anonymous
What is the mathmatical formula
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.